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• 当前位置：创新互联 >> 常见问题 >> 前端开发 >> XML教程 >> FireFox对XML的处理兼容IE的节点处理方法

FireFox对XML的处理兼容IE的节点处理方法

• 作者：创新互联 文章来源：前端开发部 点击数： 更新时间：2008-09-13
• 使Firefox对xml的处理兼容IE的节点处理方法。具体代码列出如下。
  具体代码如下。
  <! DOCTYPE Html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" >
  < HTML >
  < HEAD >
  < TITLE >  使firefox对xml的处理兼容IE的selectSingleNode selectNodes方法  </ TITLE >
  < META  NAME ="Author"  CONTENT ="emu" >
  < META  NAME ="KeyWords"  CONTENT ="firefox IE selectSingleNode selectNodes" >
  < META  NAME ="Description"  CONTENT ="使firefox可以支持selectSingleNode selectNodes方法" >
  < SCRIPT  LANGUAGE ="javascript" >
  <!--
  var  isIE  =   !! document.all;
  function  parseXML(st){
       if (isIE){
           var  result  =   new  ActiveXObject( " microsoft.XMLDOM " );
          result.loadXML(st);
      } else {
           var  parser  =   new  DOMParser();
           var  result  =  parser.parseFromString(st,  " text/xml " );
      }
       return  result;
  }
  if ( ! isIE){
       var  ex;
      XMLDocument.PRototype.__proto__.__defineGetter__( " xml " ,  function (){
           try {
               return   new  XMLSerializer().serializeToString( this );
          } catch (ex){
               var  d  =  document.createElement( " div " );
              d.appendChild( this .cloneNode( true ));
               return  d.innerHTML;
          }
      });
      Element.prototype.__proto__.__defineGetter__( " xml " ,  function (){
           try {
               return   new  XMLSerializer().serializeToString( this );
          } catch (ex){
               var  d  =  document.createElement( " div " );
              d.appendChild( this .cloneNode( true ));
               return  d.innerHTML;
          }
      });
      XMLDocument.prototype.__proto__.__defineGetter__( " text " ,  function (){
           return   this .firstChild.textContent
      });
      Element.prototype.__proto__.__defineGetter__( " text " ,  function (){
           return   this .textContent
      });
      XMLDocument.prototype.selectSingleNode = Element.prototype.selectSingleNode = function (XPath){
           var  x = this .selectNodes(xpath)
           if ( ! x    x.length < 1 ) return   null ;
           return  x[ 0 ];
      }
      XMLDocument.prototype.selectNodes = Element.prototype.selectNodes = function (xpath){
           var  xpe  =   new  XPathEvaluator();
           var  nsResolver  =  xpe.createNSResolver( this .ownerDocument  ==   null   ?
               this .documentElement :  this .ownerDocument.documentElement);
           var  result  =  xpe.evaluate(xpath,  this , nsResolver,  0 ,  null );
           var  found  =  [];
           var  res;
           while  (res  =  result.iterateNext())
              found.push(res);
           return  found;
      }
  }
  var  x  =  parseXML( " <people>  <person first-name=\ " eric\ "  middle-initial=\ " H\ "  last-name=\ " jung\ " >    <address street=\ " 321  south st\ "  city=\ " denver\ "  state=\ " co\ "  country=\ " usa\ " />    <address street=\ " 123  main st\ "  city=\ " arlington\ "  state=\ " ma\ "  country=\ " usa\ " />  </person>  <person first-name=\ " jed\ "  last-name=\ " brown\ " >    <address street=\ " 321  north st\ "  city=\ " atlanta\ "  state=\ " ga\ "  country=\ " usa\ " />    <address street=\ " 123  west st\ "  city=\ " seattle\ "  state=\ " wa\ "  country=\ " usa\ " />    <address street=\ " 321  south avenue\ "  city=\ " denver\ "  state=\ " co\ "  country=\ " usa\ " />  </person></people> " );
  alert( " 搜索所有人的姓氏（last-name） " )
  var  results  =  x.selectNodes( " //person/@last-name " );
  for  ( var  i = 0 ; i < results.length;i ++ )
    alert( " Person # "   +  i  +   "  has the last name  "   +  results[i].nodeValue);
  alert( " 搜索第二个人 " );
  //  IE是以0为下标基数的，而不是1
  if ( ! document.all)
      results  =  x.selectSingleNode( " /people/person[2] " );
  else
      results  =  x.selectSingleNode( " /people/person[1] " );
  alert(results.xml)
  alert( " 获得住址在donver街上的人 " );
  results  =  x.selectNodes( " //person[address/@city='denver'] " );
  for  ( var  i = 0 ; i < results.length;i ++ )alert(results[i].xml)
  if ( ! document.all){
       //  获得所有街名中带south的地址
      results  =  x.selectNodes( " //address[contains(@street, 'south')] " );
      alert(results[ 0 ].xml);
  } else {
      alert( " IE不支持 //address[contains(@street, 'south')] 这种查询方式 " )
  }
  // -->
  </ SCRIPT >
  </ HEAD >
  < BODY >
  </ BODY >
  </ HTML >
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